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LT1376CS Datasheet(PDF) 25 Page - Linear Technology |
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LT1376CS Datasheet(HTML) 25 Page - Linear Technology |
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25 / 28 page ![]() 25 LT1375/LT1376 APPLICATIONS INFORMATION INDUCTOR VALUE Unlike buck converters, positive-to-negative converters cannot use large inductor values to reduce output ripple voltage. At 500kHz, values larger than 25 µH make almost no change in output ripple. The graph in Figure 19 shows peak-to-peak output ripple voltage for a 5V to – 5V con- verter versus inductor value. The criteria for choosing the inductor is therefore typically based on ensuring that peak switch current rating is not exceeded. This gives the lowest value of inductance that can be used, but in some cases (lower output load currents) it may give a value that creates unnecessarily high output ripple voltage. A com- promise value is often chosen that reduces output ripple. As you can see from the graph, large inductors will not give arbitrarily low ripple, but small inductors can give high ripple. INDUCTOR SIZE ( µH) 0 150 120 90 60 30 0 20 1375/76 F19 5 10 15 25 5V TO –5V CONVERTER OUTPUT CAPACITOR ESR = 0.1 Ω ILOAD = 0.25A ILOAD = 0.1A Figure 19. Ripple Voltage on Positive-to-Negative Converter The difficulty in calculating the minimum inductor size needed is that you must first know whether the switcher will be in continuous or discontinuous mode at the critical point where switch current is 1.5A. The first step is to use the following formula to calculate the load current where the switcher must use continuous mode. If your load current is less than this, use the discontinuous mode formula to calculate minimum inductor needed. If load current is higher, use the continuous mode formula. Output current where continuous mode is needed: I VI VV VV V CONT IN P IN OUT IN OUT F = () ( ) + () ++ () 22 4 Minimum inductor discontinuous mode: L VI fI MIN OUT OUT P = ()( ) ()( ) 2 2 Minimum inductor continuous mode: L VV fV V I I VV V MIN IN OUT IN OUT P OUT OUT F IN = ()( ) () + () −+ + () 21 For the example above, with maximum load current of 0.25A: IA CONT = () ( ) + () ++ () = 51 5 4 5 5 550 5 037 22 . . . This says that discontinuous mode can be used and the minimum inductor needed is found from: LH MIN = ()( ) () = 25 0 25 500 10 1 5 22 3 2 . •. . µ In practice, the inductor should be increased by about 30% over the calculated minimum to handle losses and variations in value. This suggests a minimum inductor of 3 µH for this application, but looking at the ripple voltage chart shows that output ripple voltage could be reduced by a factor of two by using a 15 µH inductor. There is no rule |
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